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Which point is on the circle centered at the origin with a radius of 5 units?

Distance formula: (x2 – x2)2 + (v2 - Yo)?
(2, 721)
(2, V23)
(2, 1)
(2,3)

User Malia
by
5.1k points

2 Answers

1 vote

Answer:2, square root of 21 just took the test!

Explanation:

User Cduhn
by
4.8k points
1 vote

Answer:

(2,√21)

Explanation:

The circle centered at the origin has equation:


{x}^(2) + {y}^(2) = 25

Any point that satisfies this equation lie on this circle.

When x=2, we substitute and solve for y.


{2}^(2) + {y}^(2) = 25 \\ 4 + {y}^(2) = 25 \\ {y}^(2) = 25 - 4 \\ {y}^(2) = 21

Take square root to get:


y = \pm √(21)

Therefore (2,-√21) and (2,√21) are on this circle.

From the options, (2,√21) is the correct answer

User Artenes Nogueira
by
5.4k points