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If the temperature is held constant during this process and the final pressure is 703 torr , what is the volume of the bulb that was originally filled with gas

User Peitek
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1 Answer

2 votes

Answer:


2.42liter

Step-by-step explanation:

The question is incomplete; you need some additional data.

I will assume the missing data from a similar question and keep the final pressure of 703 torr given in your question.

An ideal gas at a pressure of 1.20 atm is contained in a bulb of unknown volume. A stopcock is used to connect this bulb with a previously evacuated bulb that has a volume of 0.720 L as shown here. When the stopcock is opened the gas expands into the empty bulb

If the temperature is held constant during this process and the final pressure is 703 torr , what is the volume of the bulb that was originally filled with gas?

Solution

Since the amount of gas and the temperature remain constant, we may use Boyle's law:


PV=constant\\\\P_1V_1=P_2V_2

Form the data:


P_1=1.20atm\\\\P_2=703torr\\\\V_1=unknown\\\\V_2=V_1+0.720liter

1. Convert 703 torr to atm:


P_2=703torr* 1atm/760torr=0.925atm

2. Sustitute the data in the equation:


1.2atm* V_1=0.925atm*(V_1+0.720liter)

3. Solve:


1.2V_1=0.925V_1+ 0.666liter\\\\0.275V_1=0.666liter\\\\V_1=2.4218liter\approx 2.42liter

The answer is rounded to 3 significant figures, according to the data.

User Tom Verelst
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