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If y varies inversely with the square of r, what is the constant of proportionality when y - 10 and 1 = 5?

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Question:

If y varies inversely with the square of r, what is the constant of proportionality when y =10 and r = 5?

Answer:

The constant of proportionality is 250

Solution:

Given that,

y varies inversely with the square of r

Which means,


y \propto (1)/(r^2)\\\\y = k * (1)/(r^2)

Where, "k" is constant of proportionality

Subtitute y = 10 and r = 5


10 = k * (1)/(5^2)\\\\10 = k * (1)/(25)\\\\k = 10 * 25\\\\k = 250

Thus the constant of proportionality is 250

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