Answer:
Explanation:
Given that the owner of a motel has 2900 m of fencing and wants to enclose a rectangular plot of land that borders a straight highway.
Fencing is used for 2times length and 1 width if highway side is taken as width
So we have 2l+w = 2900
Or w = 2900-2l
Area of the rectangular region = lw
![A(l) = l(2900-2l) = 2900l-2l^2\\](https://img.qammunity.org/2021/formulas/mathematics/college/412rrbqwws8wmxfhix51nb9enmx3m6qw11.png)
Use derivative test to find the maximum
![A'(l) = 2900-4l\\A](https://img.qammunity.org/2021/formulas/mathematics/college/8zyyi62pfo4qt49u176wsdnmkrq2tbrjnc.png)
So maximum when I derivative =0
i.e when
![l =(2900)/(4) =725](https://img.qammunity.org/2021/formulas/mathematics/college/c2eyj4clsw2526wi4yyiylxpoxa2y2gzua.png)
Largest area = A(725)
=
![725(2900-2*725)\\= 1051250](https://img.qammunity.org/2021/formulas/mathematics/college/m3vlytm7wpkhy5t8aat6orge1qswaelyo7.png)
1051250 sqm is area maximum