Question

al aplicar una fuerza de 2 N sobre un muelle este se alarga 4cm.¿cuanto se alargara si la fuerza es el triple?¿que fuerza tendriamos que hacer para que el alargamiento fuera de 6cm?

Answer 1

1) 12 cm

2) 3 N

Step-by-step explanation:

1)

The relationship between force and elongation in a spring is given by Hooke's law:

`F=kx`

where

F is the force applied

k is the spring constant

x is the elongation

For the spring in this problem, at the beginning we have:

`F=2 N`

`x=4 cm`

So the spring constant is

`k=(F)/(x)=(2N)/(4 cm)=0.5 N/cm`

Later, the force is tripled, so the new force is

`F'=3F=3(2)=6 N`

Therefore, the new elongation is

`x'=(F')/(k)=(6)/(0.5)=12 cm`

2)

In this second problem, we know that the elongation of the spring now is

`x=6 cm`

From part a), we know that the spring constant is

`k=0.5 N/cm`

Therefore, we can use the following equation to find the force:

`F=kx`

And substituting k and x, we find:

`F=(0.5)(6)=3 N`

So, the force to produce an elongation of 6 cm must be 3 N.