Question

A man pushes a cart with force of 120-N at an angle of 50 degrees with the ground. If he walks a horizontal displacement of 20-m going to cashier who’s much work is done!

Answer 1

1543 J

Step-by-step explanation:

The work done by a force when moving an object is given by the equation:

`W=Fd cos \theta`

where:

F is the magnitude of the force applied on the object

d is the displacement of the object

`\theta` is the angle between the direction of the force and of the displacement

For the cart pushed in this problem, we have:

`F=120 N` is the force applied by the man

`d=20 m` is the displacement of the cart

`\theta=50^(\circ)` is the angle between the directions of the force and of the displacement

Solving for W, we find the work:

`W=(120)(20)(cos 50^(\circ))=1543 J`