Question

A line passes through the point (-1,-5) and has a slope of -5.

Write an equation in slope-intercept form for this line.

Answer 1

To write the equation of a line in slope-intercept form, we need the slope and the y-intercept. By substituting the given values into the equation, we find that the equation of the line is y = -5x - 10.

Step-by-step explanation:

To write the equation of a line in slope-intercept form (y = mx + b), we need the slope (m) and the y-intercept (b).

Given that the line passes through the point (-1, -5) and has a slope of -5, we can plug these values into the equation to find the y-intercept (b).

We have:

• x = -1
• y = -5
• slope (m) = -5

By substituting these values into the equation, we get:

-5 = -5*(-1) + b

-5 = 5 + b

b = -10

So the equation of the line in slope-intercept form is:

y = -5x - 10

Answer 2

hello!

We're given a point that the line intersects and its slope.

Let's use Point-slope:-

`\boxed{y-y1=m(x-x1)}`

y1 = -5

m=-5

x1=-1

`\boxed{y-(-5)=-5(x-(-1)}`

`\boxed{y+5=-5(x+1)}`

Convert to slope-intercept:-

`\boxed{y+5=-5x-5}`

`\boxed{y=-5x-5-5}`

Finally,

`\bigstar{\boxed{\pmb{y=-5x-10}}`

note:-

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)