Question

what force much be applied to stop a 1400kg car that is initially traveling at 13 m/s over a 5 second time period

Answer 1

As per Provided Information

• Mass of car m is 1400Kg
• Initial velocity u is 13m/s
• Time taken to stop t is 5 second .
• Final velocity v is 0m/s

we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.

`\boxed{\bf \: a \: = ((v - u))/(t)}`

Substituting the value and let's solve it

`\longrightarrow\sf \: a \: = (0 - 13)/(5) \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^( - 2)`

Now, let's calculate the force applied to stop the car .

`\pink{\boxed{\bf \: F = ma}}`

Substituting the value we get

`\longrightarrow \sf \: F = 1400 * ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N`

Here , negative sign show that the " Force is acting in opposite direction of the motion"

Therefore,

• 3640 Newton force is required to stop the car .