Question

For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at equilibrium are [ A ] = 9.68 × 10 − 2 M , P B = 9.54 × 10 3 Pa , [ C ] = 14.64 M , [ D ] = 10.11 M , and P E = 9.56 × 10 4 torr . Calculate the thermodynamic equilibrium constant, K.

Answer 1

`2.55*10^{11`

Step-by-step explanation:

Equation for the heterogeneous system is given as:

`2A_((aq)) + 3 B_((g)) + C_((l))` ⇄
`2D_((s))`
`+`
`3E_((g))`

The concentrations and pressures at equilibrium are:

`[A] = 9.68*10^(-2)M`

`P_B = 9.54*10^3Pa`

`[C]=14.64M`

`[D]=10.11M`

`P_E=9.56*10^4torr`

If we convert both pressure into bar; we have:

`P_B = 9.54*10^3Pa`

`P_B = (9.54*10^3)*(1)/(10^5) bar`

`P_B=9.54*10^(-2)bar`

`P_E=9.56*10^4torr`

1 torr = 0.001333 bar

`9.54*10^4 *0.001333 = 127.5 bar`

`K=([P_E]^3)/([A]^2[P_B]^3)`

`K=((127.5)^3)/((9.68*10^(-2))^2(9.54*10^(-2))^3)`

`K=2.55*10^{11`