Answer:
For 0.027 moles CH3COOH we have 0.108 moles H ≈ 1.1 *10^-1 moles H
Step-by-step explanation:
Step 1: Data given
Acetic acid = CH3COOH
Number of moles oxygen in the sample = 0.054 moles
Step 2: calculate moles CH3COOH
In 1 mol CH3COOH we have 2 moles O
For 0.054 moles Oxygen we have 0.054/2 = 0.027 moles CH3COOH
Step 3: Calculate moles H
In 1 mol CH3COOH we have 4 moles H
For 0.027 moles CH3COOH we have 4*0.027 = 0.108 moles H ≈ 1.1 *10^-1 moles