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For a game, Tony has a rectangle drawn on a piece of paper that has an area of 18 in.^2. What should he do to the dimensions in order to have a similar rectangle that's area is only 2 in.^2?

options:

Divide them by nine.

Divide them by six.

Divide them by three.

Multiply them by three.

User MrMikimn
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2 Answers

6 votes

Answer:

Divide them by three.

User Webbertiger
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2 votes

We have to divide the dimensions by 9 to get a similar rectangle that's area is only 2 in.^2

Solution:

Given that,

For a game, Tony has a rectangle drawn on a piece of paper that has an area of 18 in.^2

In order to have a similar rectangle that's area is only 2 in.^2

Thus, we need to find the scale factor

Let "c" be the scale factor

Let "x" be the area of original rectangle

Let "y" be the area of dilated rectangle

Therefore,


c = (y)/(x)\\\\c = (2)/(18)\\\\c = (1)/(9)

Therefore, we have to divide the dimensions by 9 to get a similar rectangle that's area is only 2 in.^2

User Ivan Shumilin
by
4.0k points