Question

Let f(x)= x2 - 14 and g(x) = 6-X.
Find (fq)(7).

Answer 1

`(fg)(7) = - 35`

Explanation:

The given functions are:

`f(x) = {x}^(2) - 14`

and

`g(x) = 6 - x`

We want to to find

`(fg)(7)`

Note that:

`(fg)(x) = f(x) * g(x)`

We substitute the functions to obtain:

`(fg)(x) = ( {x}^(2) -1 4 ) * (6 - x)`

We now substitute x=7, to get:

`(fg)(7) = ( {7}^(2) -1 4 ) * (6 - 7)`

This implies that

`(fg)(7) =( 49-1 4 ) * (6 - 7)`

`(fg)(7) = 35 * - 1 = - 35`