Question

Calculate the magnitude of the force exerted by each wire on a 1.20-m length of the other.

Answer 1

Incomplete question.The complete question is attached below as screenshot along with figure

Answer:

`F=6.00*10^(-6)N`

Force is repulsive

Step-by-step explanation:

Given data

Current I₁=5.00A

Current I₂=2.00A

Length L=1.20 m

Radius r=0.400m

To find

Force F

Solution

As the force is repulsive because currents are in opposite direction

From repulsive force we know that:

`F=(u_(o)I_(1)I_(2)L)/(2\pi r)`

Substitute the given values

`F=(u_(o)(5.00A)(2.00A)(1.20m))/(2\pi (0.400m))\\ F=6.00*10^(-6)N`