Question

Say you have two parallel current-carrying wires, each carrying a current of 1.0 A and with a distance of 1.0 m between them. What is the magnitude of the force per unit length experienced by each wire

Answer 1

`(F)/(l)=2* 10^(-7)\ N/m`

Step-by-step explanation:

Given,

current in the wire I₁ = 1 A

I₂ = 1 A

distance between them, r = 1 m

using Force per unit length formula

`(F)/(l)=(\mu_0I_1I_2)/(2\pi r)`

`\mu_0 = magnetic\ permeability\ of\ free\ space = 4\pi* 10^(-7)`

`(F)/(l)=(4\pi *10^(-7)* 1* 1)/(2\pi* 1)`

`(F)/(l)=2* 10^(-7)\ N/m`

Hence, the magnitude of force per unit length is equal to
`(F)/(l)=2* 10^(-7)\ N/m`