Answer:
0.2 moles of solute are in 200 mL
Step-by-step explanation:
If we assume an aqueous solution, the solvent's density is 1g/mL
Solvent's volume = 200 mL
Solvent's density = Solvent's mass / Solvent's volume
Solvent's mass = solvent's density . solvent's volume → 200 mL . 1g/mL = 200 g
1 m means molality, we have 1 mol of solute in 1000 g of solvent, but in here the mass of solvent is 200 g. Let's make a rule of three:
1000 g of solvent have 1 mol of solute
Therefore, 200 g of solvent must have (200 .1) / 1000 = 0.2 moles