Question

What was the value of x and y for the following equations? Equation 1: 2/3 (x-6) = 6 Equation 2: 2/3y - 6 = 6 x = 15, y = 15 x = 18, y = 15 x = 18, y = 18 x = 15, y = 18

Answer 1

The value of x is 15 and value of y is 18

Solution:

Given equations are:

`(2)/(3)(x - 6) = 6\\\\(2)/(3)y - 6 = 6`

From first equation,

`(2)/(3)(x - 6) = 6\\\\Remove\ the\ parenthesis\ and\ solve\\\\(2)/(3)x - (2)/(3) * 6 = 6\\\\(2)/(3)x - 4 = 6\\\\Move\ the\ constant\ from\ left\ side\ to\ right\ side\\\\(2)/(3)x = 6 + 4\\\\(2)/(3)x= 10\\\\2x = 30\\\\Divide\ both\ sides\ by 2\\\\x = 15`

From second equation,

`(2)/(3)y - 6 = 6\\\\Move\ the\ constant\ from\ left\ side\ to\ right\ side\ of\ equation\\\\(2)/(3)y = 6 + 6\\\\(2)/(3)y = 12\\\\2y = 36\\\\Divide\ both\ sides\ by\ 2\\\\y = 18`

Thus value of x is 15 and value of y is 18