Question

A phone cord is 4.67 m long. The cord has a mass of 0.192 kg. A transverse wave pulse is produced by plucking one end of the taunt cord. The pulse makes four trips down and back along the cord in 0.794 s.

What is the tension in the cord?

Answer 1

91.017N

Step-by-step explanation:

Parameters

L=4.67m, m=0.192kg, t = 0.794s, The pulse makes four trips down and back along the cord, we have 4 +4 =8 trips( to and fro)

so N= no of trips = 8, From Wave speed(V) = N *L/t , we have :

V= 8*4.67/0.794 = 47.0529 m/s.

We compute the cords mass per length, Let it be P

P = M/L = 0.192/4.67 = 0.04111 kg/m

From T = P * V^2 where T = Tension, we have

T = 0.04111 * (47.0529)^2

T = 91.017N.

The tension in the cord is 91.017N