Question

If I have 2.9 L of gas at a pressure of 5.0 atm and a temperature of 50.0 °C, what will be the

temperature of the gas if I decrease the volume of the gas to 2.4 L and decrease the
pressure to 3.0 atm?

Answer 1

160.4K

Step-by-step explanation:

Given parameters:

Initial volume of gas = 2.9L

Initial pressure of gas = 5atm

Initial temperature = 50°C

Final volume = 2.4L

Final pressure of gas= 3atm

Unknown:

Final temperature = ?

Solution:

To solve this problem, we have to apply the combined gas laws.

Mathematically, the law is expressed as;

`(P_(1)V_(1) )/(T_(1) ) = (P_(2)V_(2) )/(T_(2) )`

where P₁ is the initial pressure

V₁ is the initial volume

T₁ is the initial temperature

P₂ is the final pressure

V₂ is the final volume

T₂ is the final temperature

Since T₂ is the unknown, we must solve for it.

convert T₁ from °C to K;

T₁ = 273 + 50 = 323K

Now insert the parameters;

`(5 x 2.9)/(323) = (3 x 2.4)/(T_(2) )`

`T_(2)` = 160.4K