Answer:
h(3) = 7
h'(3) = 15/7
Explanation:
h(3) = f(g(3)) = f(5(3²)+4)
h(3) = f(49)
h(x) = (5x² + 4)^½
h'(x) = ½[(5x² + 4)^-½] × 10x
h'(x) = 5x[(5x² + 4)^-½]
h'(3) = 5(3)/7 = 15/7
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