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One x-intercept for a parabola is at the point

(2,0). Use the quadratic formula to find the
other x-intercept for the parabola defined by
this equation:
y=x² – 3x + 2

1 Answer

7 votes

Answer:

The other x-intercept is the point (1,0)

Explanation:

we have


y=x^2-3x+2

The formula to solve a quadratic equation of the form


ax^(2) +bx+c=0

is equal to


x=\frac{-b\pm\sqrt{b^(2)-4ac}} {2a}

in this problem we have


y=x^2-3x+2

equate to zero


x^2-3x+2=0

so


a=1\\b=-3\\c=2

substitute in the formula


x=\frac{-(-3)\pm\sqrt{-3^(2)-4(1)(2)}} {2(1)}


x=\frac{3\pm√(1)} {2}


x=\frac{3\pm1} {2}

so


x=\frac{3+1} {2}=2


x=\frac{3-1} {2}=1

therefore

The other x-intercept is the point (1,0)

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