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What volume will 1.27 moles of helium gas occupy at stp

User Hosny
by
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2 Answers

7 votes

Answer:

28.45L

Step-by-step explanation:

User Bscan
by
4.9k points
5 votes

Answer:

28.45L

Step-by-step explanation:

1mole of a gas occupy 22.4L at stp. This implies that 1mole of He also occupy 22.4L at stp.

Now if 1mole of He occupied 22.4L at stp, then, 1.27mol will occupy = 1.27x22.4 = 28.45L

User AlienDeg
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4.0k points