Question

A large tower is to be supported by a series of steel wires. It is estimated that the load on each wire will be 11,100 N (2500 lb f ). Determine the minimum required wire diameter assuming a factor of safety of 2 and a yield strength of 1030 MPa (150,000 psi).

Answer 1

5.24m

Step-by-step explanation:

Data given

force, F= 11,100N

safety factor,N=2

yield strength, =1030MPa

To determine the minimum diameter, we first determine the working strength which is expressed as

`working strength=(yield strength)/(safty factor)\\ Working strength =1030/2=515MPa\\`

Since also the working strength is define as the ration of the force to the area, we have

`515=(11100)/(A)\\ A=21.55m^(2)`

hence the required diameter is given as

`A=\pi d^2/4\\d=\sqrt{(4*21.55 )/(\pi )} \\d=5.24m`