Question

A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode composed of copper in a 1.0 M copper(I) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C .

Answer 1

Answer: The standard potential of the cell is 0.77 V

Step-by-step explanation:

We know that:

`E^o_(Ni^(2+)/Ni)=-0.25V\\E^o_(Cu^(+)/Cu)=0.52V`

The substance having highest positive
`E^o` reduction potential will always get reduced and will undergo reduction reaction.

The half reaction follows:

Oxidation half reaction:
`Ni(s)\rightarrow Ni^(2+)(aq)+2e^-`

Reduction half reaction:
`Cu^(+)(aq)+e^-\rightarrow Cu(s)` ( × 2)

To calculate the
`E^o_(cell)` of the reaction, we use the equation:

`E^o_(cell)=E^o_(cathode)-E^o_(anode)`

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation follows:

`E^o_(cell)=0.52-(-0.25)=0.77V`

Hence, the standard potential of the cell is 0.77 V