Question

Does the point (1, -1) lie on the line (-10x + 5y = -8)? Explain why/why not.​

Answer 1

hello!

In order to see whether or not a point lies on the line, we need to plug in the x-coordinate (instead of x) and plug the y-coordinate instead of y.

In this case, the x-coordinate is:-

`\mathrm{1}`

and the y-coordinate is:-

`\mathrm{-1}`

Plug in the values:-

`\mathbf{-10(1)+5(-1)=-8}`

`\mathbf{-10-5=-8}`

`\mathbf{-15=-8}`

Huh?!

As you can see, we ended up with a false statement.

Hence, the answer is:-

`\bigstar{\boxed{\pmb{The~point~(1,-1)~doesn't~lie~on~the~line}}}`

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)

Answer 2

the point (1, -1) doesn’t lie on the line (-10x + 5y = -8)

Explanation:

Generaly , a point A(x₀ , y₀) lies on the line of equation ax + by = c

If its coordinates verify the equation which means

When we replace x by x₀ and y by y₀ in our equation we get ax₀ + by₀ = c

Then

just replace x by 1 and y by -1 in the equation: -10x + 5y = -8

We get , -10(1) + 5(-1) = -10 - 5 = -15

Since -15 ≠ -8 then (1 , -1) don’t verify the equation

Hence , the point (1, -1) doesn’t lie on the line (-10x + 5y = -8)