Question

How many electrons must be removed from an electrically neutral silver dollar to give it a charge of +3.5x10^-6C?

Answer 1

`2.19\cdot 10^(13)`

Step-by-step explanation:

The electron is a fundamental particle, with a charge of

`e=-1.6\cdot 10^(-19)C`

which is also known as fundamental charge.

For an object having N excess electrons, the total charge on the object is

`Q=Ne` (1)

where e is the charge of the electron.

For the object in this problem, its charge is

`Q=+3.5\cdot 10^(-6) C`

This can be obtained by removing a negative charge equal to

`Q=-3.5\cdot 10^(-6)C`

Substituting into (1) and solving for N, we can find the number of electrons:

`N=(Q)/(e)=(-3.5\cdot 10^(-6))/(-1.6\cdot 10^(-19))=2.19\cdot 10^(13)`