Answer:
0.50
Explanation:
Given that a box contains three coins: two regular and one fake one-sided coin (P(H) = 1) You pick a coin at random and toss it.
Probability of selecting any one coin = 1/3
The coins are regular 1, regular 2 , fake
P for head 0.5 0.5 1
Probability for head =
![(1)/(3) (1+0.5+0.5) = 0.6667](https://img.qammunity.org/2021/formulas/mathematics/high-school/abrc342vaf6p1vkkes1wtojdlnhh70sn8h.png)
using total probability theorem for mutually exclusive and exhaustive)
Probability that coin is not fake/head =
![(0.5+0.5)/(1+0.5+0.5) \\= 0.5](https://img.qammunity.org/2021/formulas/mathematics/high-school/b9v2ovvbmfgbfeij0jyw22bss0p1sjoazv.png)