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Find the value of each trigonometric ratio

Find the value of each trigonometric ratio-example-1
User Syed Aqeel
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1 Answer

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The value of each trigonometric ratio is


$\sin A=(15)/(17), \ \cos A=(8)/(17), \ \tan A =(15)/(8)


$\csc A=(17)/(15), \ \sec A=(17)/(8), \ \cot A =(8)/(15)

Solution:

The given triangle is right triangle.

AC (hypotenuse) = 34, AB (adjacent) = 16, BC (opposite) = 30

To find the trigonometric ratios:

Using trigonometric formulas for right triangle,


$\sin \theta=\frac{\text { opposite }}{\text { hypotenuse }}


$\sin A=(BC)/(AC)


$\sin A=(30)/(34)=(15)/(17)


$\cos \theta=\frac{\text { adjacent }}{\text { hypotenuse }}


$\cos A=(AB)/(AC)


$\cos A=(16)/(34)=(8)/(17)


$\tan \theta=\frac{\text { opposite }}{\text { adjacent }}


$\tan A=(BC)/(AB)


$\tan A=(30)/(16)=(15)/(8)


$\csc A =(1)/(\sin A)


$\csc A =(17)/(15)


$\sec A =(1)/(\cos A)


$\sec A =(17)/(8)


$\cot A =(1)/(\tan A)


$\cot A =(8)/(15)

Hence the value of each trigonometric ratio is


$\sin A=(15)/(17), \ \cos A=(8)/(17), \ \tan A =(15)/(8)


$\csc A=(17)/(15), \ \sec A=(17)/(8), \ \cot A =(8)/(15)

User Genna
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