Answer:
![(x-2)/(-1) =(y-4)/(1) =(z-4)/(-4) =t](https://img.qammunity.org/2021/formulas/mathematics/college/xpk7fvfgyns1gu8ma94q7sw8pac8ve4cqb.png)
Explanation:
Given that a line passes through P(2,4,4)
Also the line is perpendicular to the plane
![-1x+1y-4z=1.](https://img.qammunity.org/2021/formulas/mathematics/college/5vhrjrd0moxfmaxq7f1ln85zrtg01rmb0t.png)
From the equation of the plane we can say that normal to the plane has direction ratios as (-1,1,-4)
Since the required line is also perpendicular to the plane, the direction ratios of the required line is
(-1,1,4)
It passes through (2,4,4)
If Q(x,y,z) are general points on the line then
Direction ratios of PQ are = (x-2, y-4, z-4)
These are proportional to (-1,1,4)
So parametric form of the line is
![(x-2)/(-1) =(y-4)/(1) =(z-4)/(-4) =t](https://img.qammunity.org/2021/formulas/mathematics/college/xpk7fvfgyns1gu8ma94q7sw8pac8ve4cqb.png)
Whem t=0 we get the point P.