Question

If the momentum of a 100 kg moped travelling at 10 m/s was transferred completely to a 25.0 kg cement traffic barrier, what would the final speed of the barrier be

Answer 1

the final speed of the barrier would be 40m/s

Step-by-step explanation:

Hello, I think I can help you with this.

the momentum is given by:

P=m*v, where P is the momentum, m is the mass of the object and v is the speed of the object.

if the momentum is transferred completely it means that the barrier will have the same amount of momentum, in other terms

momentum of the moped=momentum of the barrier

mass of the moped*speed of the moped=*speed of the barrier

let's isolate the final speed of the barrier

final speed of the barrier is

`=(mass\ of\ the\ moped*speed\ of\ the\ moped)/(mass\ of\ the\ barrier ) \\\\put the values \\\\=(100kg*10m/s)/(25kg) \\=40 m/s`

so, the speed is 40 m/s