Question

Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done during this process.

Answer 1

`W=-251096.465\ J` negativesign denotes thatthe work is consumed by the system.

Step-by-step explanation:

Given:

Isothermal process.

initial temperature,
`T_1=300\ K`

initial pressure,
`P_1=150kPa`

initial volume,
`V_1=0.2\ m^3`

final pressure,
`P_2=800\ kPa`

The work done during an isothermal process is given by:

`W=P_1.V_1* ln((P_1)/(P_2) )`

`W=150* 1000* \ln(150)/(800)`

`W=-251096.465\ J` negativesign denotes thatthe work is consumed by the system.