Question

A football punter accelerates a .55 kg football

Answer 1

17.6 N

Step-by-step explanation:

The force exerted by the punter on the football is equal to the rate of change of momentum of the football:

`F=(\Delta p)/(\Delta t)`

where

`\Delta p` is the change in momentum of the football

`\Delta t=0.25 s` is the time elapsed

The change in momentum can be written as

`\Delta p = m(v-u)`

where

m = 0.55 kg is the mass of the football

u = 0 is the initial velocity (the ball starts from rest)

v = 8.0 m/s is the final velocity

Combining the two equations and substituting the values, we find the force exerted on the ball:

`F=(m(v-u))/(\Delta t)=((0.55)(8.0-0))/(0.25)=17.6 N`