Question

The charge density of radius 12.0 cm isgiven by with a = 1.40 μC/m 3 and r ismeasured radially outward from theorigin. What is the electric potential atpoint A, a distance 40.0 cm above thedisk? Hint: you will need to integrate thenon uniform charge distribution to findthe electric potential.

Answer 1

The electric potential of the uniformly charge disk is 1392.1 V

Step-by-step explanation:

Electric potential, for a uniformly charged disk at a distance A, is given as;

`V = (\sigma)/(2 \epsilon) [√(A^2 +R^2) -A]`

Where;

σ is the charge density = 1.40 μC/m³

ε is the permittivity of free space = 8.85 x 10⁻¹²

A is the distance above the disk = 40 cm = 0.4 m

R is the radius of the disk = 0.12 m

Substitute in these values into the equation above, we will have

`V = (1.4 X 10^(-6))/(2X8,85X10^(-12))[√(0.4^2 +0.12^2)-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V`

Therefore, the electric potential of the uniformly charge disk is 1392.1 V