Question

A lab group made a copper amine stock solution with a concentration of 0.02 M. A group member transfers 9.27 mL of this solution to a 25 mL volumetric flask and dilutes to the line with water. What is the concentration of the resulting solution?

Answer 1

Answer : The concentration of the resulting solution is, 0.0074 M

Explanation :

Formula used :

`M_1V_1=M_2V_2`

where,

`M_1\text{ and }V_1` are the initial molarity and volume of stock solution.

`M_2\text{ and }V_2` are the final molarity and volume of diluted solution.

We are given:

`M_1=0.02M\\V_1=9.27mL\\M_2=?\\V_2=25mL`

Putting values in above equation, we get:

`0.02M* 9.27mL=M_2* 25mL\\\\M_2=0.0074M`

Hence, the concentration of the resulting solution is, 0.0074 M