Answer:
Explanation:
When a fair coin is tossed 100 times X no of heads is binomial with n =100 and p = 0.50
Mean = np = 50 and Variance = npq = 25
so std dev = 5
When approximated to normal
X : no of heads : N(50,5)
Required probability
i)
(applying continuity correction_
= F(58.5) -F(41.5)
= 0.9554-0.0446
=0.9108
ii)
![P(-8/5<X<8/5)\\= F(1.6) -F(-1.6)\\= 0.00000](https://img.qammunity.org/2021/formulas/mathematics/college/c43cbb3r21n728whmqrv8qncv5c6jd0gh8.png)
c)
![P(X\geq 50) = P(X\geq 49.5)\\= 1-F(49.5)\\= 0.5398](https://img.qammunity.org/2021/formulas/mathematics/college/ug2bm24ofcpj0p0sld1obk0v5ki6vnmh7h.png)
d) P(X>0)
=1-0.0000
=1