Question

A force is applied to a block to move it up a 30° incline. The incline is frictionless, the block is initially at rest, F= 65.0 N and M=5.00 kg. If the block starts from rest, how far will it move in 0.550 s? Also, indicate whether the block moves up or down the incline.

Answer 1

0.96 m, upward

Step-by-step explanation:

`\theta=30^(\circ)`

`F=65 N`

`M=5 kg`

Initial velocity, u=0

`t=0.550 s`

`Fcos\theta-Mgsin\theta=Ma`

Where
`g=9.8 m/s^2`

Substitute the values

`65cos30-5* 9.8sin30=5a`

`31.8=5a`

`a=(31.8)/(5)=6.36 m/s^2`

`S=ut+(1)/(2)at^2`

`S=0+(1)/(2)(6.36)(0.55)^2=0.96 m`

Hence,the block moves upward because displacement is positive.