How would I solve this problem?

Vkubicki asked Aug 7, 2023

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9 votes

Vkubicki asked Aug 7, 2023

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26 votes

Answer:

$2x^2\\\\$

Step by step explanation:

$y=\displaystyle \int_(0)^x 2t^2 dt=\frac 23\left[t^3\right]^(x)_0=\frac 23 x^3\\\\\ y'= \frac 23 \cdot 3x^2 = 2x^2$

Nick Gowdy answered Aug 14, 2023

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