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A shipment of 17 televisions sets contains 3 defective sets. A hotel purchases 8 of these televisions sets. What is the probability that the hotel receives at least one of the defective sets?

1 Answer

5 votes

Answer:

p=0.8765

Explanation:

Let the following variables be represented as below:

Total Set,t=17

Def,d=3

Not Def,n=14

Purchases,p=8

The number of ways the hotel can receive at least one defective set in a purchase of 8 sets is calculated using the combination:-


p(\geq 1)=1-((_dC_0)(_nC_p))/((_tC_p))\\p=1-((_3C_0)(_14C_8))/((_1_7C_8))\\p=1-0.1235\\p=0.8764

So the proability of getting at least one defective unit is 0.8765

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