Question

An ideal Carnot engine extracts of heat from a high-temperature reservoir at 1200 during each cycle, and rejects heat to a low-temperature reservoir at 700K during the cycle. What is the efficiency of the engine

Answer 1

efficiency of the engine is 0.4167

Step-by-step explanation:

given data

T high = 1200 K

T low = 700 K

solution

we get here efficiency that is express as

efficiency =
`1 - (T\ low)/(T \ high )` .........................1

put here value of both temperature we get efficiency

efficiency = 1 -
`(700)/(1200)`

efficiency = 1 - 0.58333

efficiency = 0.4167

so efficiency of the engine is 0.4167