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4 votes
Which is a value of x, when 3x^2 + 4 = 40?

User Asitis
by
5.3k points

1 Answer

6 votes

To solve for x, we need to isolate the variable on one side of the equation.

3x^2 + 4 = 40

Subtract 4 from both sides:

3x^2 = 36

Divide both sides by 3:

x^2 = 12

Take the square root of both sides:

x = ±√12

Simplify:

x = ±2√3

Therefore, there are two possible values of x: x = 2√3 and x = -2√3.

User Malik Rizwan
by
5.2k points
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