Question

A velocity selector in a mass spectrometer uses a 0.150 T magnetic field. (a) What electric field strength (in volts per meter) is needed to select a speed of 4.40 ✕ 106 m/s? V/m

Answer 1

The electric field strength is
`6.6*10^(5)\ V/m`

Step-by-step explanation:

Given that,

Magnetic field = 0.150 T

Speed
`v= 4.40*10^(6)\ m/s`

We need to calculate the electric field strength

Using formula of velocity

`v=(E)/(B)`

`E=v* B`

Where, v = speed

B = magnetic field

Put the value into the formula

`E=4.40*10^(6)*0.150`

`E=660000\ V/m`

`E=6.6*10^(5)\ V/m`

Hence, The electric field strength is
`6.6*10^(5)\ V/m`