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How many moles are equal to 4.0x1023 atoms of germanium?

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Answer:

0.66 mol Ge

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

4.0 × 10²³ atoms Ge

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. Set up:
    \displaystyle 4.0 \cdot 10^(23) \ atoms \ Ge((1 \ mol \ Ge)/(6.022 \cdot 10^(23) \ atoms \ Ge))
  2. Divide:
    \displaystyle 0.664321 \ mol \ Ge

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.664321 mol Ge ≈ 0.66 mol Ge

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