Question

The electric field everywhere on the surface of a thin, spherical shell of radius 0.725 m is of magnitude 899 N/C and points radially toward the center of the sphere.What is the net charge within the sphere's surface

Answer 1

Q = -52.56 nC

Step-by-step explanation:

The electric field outside a spherical shell is given by

`E = (k*Q)/(r^(2) )`

where:

Q is the net charge

r is the radius of the spherical shell and E is the electric field magnitude.

Given:

r = 0.725 m

since the field points radially toward the center of the sphere, E = -899 N/C.

k is a constant with a value = 8.99 x 109 Nm²/C².

∴
`-899 = (8.99*10^(9) *Q)/(0.725^(2) )`

`Q = (-899*0.725^(2) )/(8.99*10^(9) )=-5.256*10^(-8)`

Q = -52.56 nC