Question

An alligator swims to the left with a constant velocity of 5 S/M

When the alligator sees a bird straight ahead, the alligator speeds up with a constant acceleration of 3 SECONDS

Answer 1

t = 0.85[s]

Step-by-step explanation:

To solve this problem we must make a complete description of this. By doing an internet search, we find the description of this problem as if of the question.

Description

"An alligator swims to the left with a constant velocity of 5 m s when the alligator season a bird straight ahead the alligator speeds up with a constant acceleration of 3 m/s^2 leftward until it reaches a final velocity of 35 Ms left work how many seconds does it take the alligator to speed up from 5 m/s to 35 m/s".

To solve this problem we must identify the initial data:

v0 = initial velocity = 5 [m/s]

a = acceleration = 3 [m/s^2]

vf = final velocity = 35[m/s]

t = time = ?

Using the following kinematic equation, we can find the time that is required.

`v_(f)=v_(0)+a*t\\35=5+35*t\\t=(35-5)/(35) \\t=0.85[s]`