Question

A steel bar of 2 m length is fixed at both ends at 20°C. The coefficient of thermal expansion is 11 x 10-6/°C and the modulus of the elasticity is 2 x 106 kg/cm2. If the temperature is changed to 18°C, then the bar will be experience a stress of

A. 22 kg/cm2 (tensile) B. 22 kg/cm2 (compressive) C. 44 kg/cm2 (compressive) D. 44 kg/cm2 (tensile)

Answer 1

C. 44 kg/cm2 (compressive).

Step-by-step explanation:

The main difference between tensile and compressive stress is that tensile stress results in elongation whereas compressive stress results in shortening.

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Answer 2

A. 22 kg/cm2 (tensile)

Step-by-step explanation:

If the temperature drops to 18C degrees (by 2 degrees), it would shrink by an amount of

`\Delta L = 11*10^(-6)*2 = 22*10^(-6) m`

The strain would be:

`\epsilon = \Delta L / L = 22*10{-6} / 2 = 11*10^(-6)`

We can calculate the stress from strain and modulus of the elasticity:

`\sigma = E\epsilon = 2*10^6 * 11*10^(-6) = 22 kg/cm^2`

This stress would be tensile because the bar shrinks