Question

If two moles of

chlorine gas reacts
with potassium iodide,
how many grams of
potassium chloride are
produced?

Answer 1

When two moles of chlorine gas react with potassium iodide, two moles of potassium chloride are produced, which have a mass of 149.1 grams, based on the molar mass of potassium chloride (74.55 g/mol).

Step-by-step explanation:

To calculate the mass of potassium chloride produced when two moles of chlorine gas react with potassium iodide, we need to use molar stoichiometry in chemical equations. The balanced chemical equation for this reaction is:

2KI + Cl2 → 2KCl + I2

From the equation, we see that two moles of potassium iodide (KI) react with one mole of chlorine gas (Cl2) to produce two moles of potassium chloride (KCl). Given that two moles of chlorine gas are reacting, we can expect to produce two moles of potassium chloride.

The molar mass of KCl is approximately 74.55 g/mol. Therefore, the mass of potassium chloride produced from two moles is:

Mass = moles × molar mass = 2 moles × 74.55 g/mol = 149.1 grams

So, 149.1 grams of potassium chloride are produced from the reaction.

Answer 2

298.2 g of KCl

Explanation:

The balance chemical equation for given single replacement reaction is as follow;

2 KI + Cl₂ → 2 KCl + I₂

Step 1: Calculate moles of KI produced:

According to balance equation,

1 mole of Cl₂ produced = 2 moles of KCl

So,

2 moles of HCl will produce = X moles of KCl

Solving for X,

X = 2 mol × 2 mol / 1 mol

X = 4 moles of KCl

Step 2: Calculate Mass of KCl as;

Mass = Moles × M.Mass

Mass = 4 mol × 74.55 g/mol

Mass = 298.2 g of KCl