Question

A compound consists of 40.00% C, 6.713% H and 53.28% O on a mass basis and has a molar mass of about 180 g/mole. Determine the molecular formula of the compound.

Answer 1

The molecular formula of the compound is
`C_6H_(12)O_6`.

Step-by-step explanation:

Let the molecular formula of the compound is
`C_xH_(y)O_z`.in

Molar mass of compound = 180 g/mol

Number of carbon atom = x

Number of hydrogen atom = y

Number of oxygen atom = z

Atomic mass of carbon = 12 g/mol

Atomic mass of hydrogen = 1 g/mol

Atomic mass of oxygen = 16 g/mol

Percentage of element in compound :

`=\frac{\text{number of atoms}* \text{Atomic mass}}{\text{molar mas of compound}}* 100`

Carbon :

`40.00\%\%=(x* 12g/mol)/(180 g/mol)* 100`

x = 46

Hydrogen :

`6.713\%=(y* 1 g/mol)/(180 g/mol)* 100`

y = 12

Oxygen:

`53.28\%=(z* 16 g/mol)/(180 g/mol)* 100`

z = 5.99 ≈ 6

The molecular formula of the compound is
`C_6H_(12)O_6`.