Question

A chemist adds 290.0mL of a 1.02/molL calcium bromide CaBr2 solution to a reaction flask. Calculate the millimoles of calcium bromide the chemist has added to the flask. Round your answer to 3 significant digits.

Answer 1

To calculate the millimoles of calcium bromide added, multiply the volume of the solution (converted to liters) by the molarity and then by 1000 to convert to millimoles, resulting in 295.8 millimoles.

Step-by-step explanation:

The question asks us to calculate the millimoles of calcium bromide (CaBr2) added to a flask, given a solution concentration and volume. To determine this, we can apply the formula:

Millimoles of solute = Volume (L) × Molarity (mol/L) × 1000 (mL/L)

First, convert the volume from milliliters to liters:
290.0 mL = 0.290 L

Now, use the given molarity of CaBr2:

1.02 mol/L

Calculating the millimoles:

Millimoles of CaBr2 = 0.290 L × 1.02 mol/L × 1000 mL/L

Millimoles of CaBr2 = 295.8

Thus, the chemist has added 295.8 millimoles of CaBr2 to the flask, rounded to three significant digits.

Answer 2

Answer : The millimoles of calcium bromide is, 296 mmol

Explanation : Given,

Volume of solution = 290.0 mL = 0.290 L

Concentration = 1.02 mol/L

Now we have to calculate the moles of calcium bromide.

`\text{Moles of calcium bromide}=\text{Concentration}* \text{Volume of solution}`

`\text{Moles of calcium bromide}=1.02mol/L* 0.290L`

`\text{Moles of calcium bromide}=0.2958mol`

`\text{Moles of calcium bromide}=295.8mmol\approx 296mmol`

Thus, the millimoles of calcium bromide is, 296 mmol