182k views
0 votes
The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 × 106 Btu/h. The combustion efficiency of the boiler is measured to be 0.7 by a hand-held flue gas analyzer. After tuning up the boiler, the combustion efficiency rises to 0.8. The boiler operates 5200 h a year intermittently. Taking the unit cost of energy to be $23/106 Btu, determine the annual energy and cost savings as a result of tuning up the boiler.

User Wonderflow
by
5.5k points

1 Answer

1 vote

Solution:

Given Information,

Heat input is (
Q_(in) ) = 5.5 ×
10^(6) Btu/h

Combustion efficiency of the boiler (
n_(furnance)) = 0.7

Combustion efficiency after turn up (
n_(furnance,now)) = 0.8

Operation Hour (t) = 5200h

Unit cost (c) =
(23 dollar)/(10^(6)Btu )

Calculate heat output from the boiler
Q_(out) =
Q_(in) x
n_(furnance)

= 5.5 x
10^(6) x 0.7

= 3.85 x
10^(6) Btu/h

Calculate the heat input to the boiler after the tune-up


(Q_(in) ){new} =
Q_(out) /
(n_(furnance) ){new}

= 3.85 x
10^(6) / 0.8

= 4.8125 x
10^(6) Btu/h

Calculate the saved energy after the tune-up


(Q_(in) ){saved} =
Q_(in) -
(Q_(in) ){new}

= 5.5 x
10^(6) - 4.8125 x
10^(6) Btu/h

= 0.6875 x
10^(6) Btu/h

Calculate the annual energy saving (
E_(Saving) )


E_(Saving) =
(Q_(in) ){saved} x t

= ( 0.6875 x
10^(6) Btu/h ) ( 5200 hr/yr)

= 3575 x
10^(6) Btu/h

Calculate the annual cost saving

Annual cost saving =
E_(Annual saving) x Unit cost

= 3575 x
10^(6) Btu/h x
(23 dollar)/(10^(6)Btu )

= 82225

User Jameek
by
6.0k points