Question

A 54.0 kg woman steps off of a diving platform with a height of 12.0 m and drops straight down into the water. If she reaches a depth of 4.9 m, what is the average magnitude of the resistance force F average exerted on her by the water

Answer 1

The average magnitude of the resistance force exerted on the woman by the water is approximately 529.2 N.

Step-by-step explanation:

The average magnitude of the resistance force exerted on the woman can be found using the equation F = mg, where F is the force, m is the mass, and g is the acceleration due to gravity. In this case, the woman's mass is 54.0 kg. The acceleration due to gravity is approximately 9.8 m/s2. Therefore, the average magnitude of the resistance force is:

F = (54.0 kg)(9.8 m/s2) = 529.2 N

So, the average magnitude of the resistance force exerted on the woman by the water is approximately 529.2 N.