Question

A 20 kg metal bar made of tin and silver lost 2 kg of its weight in the water. If 10 kg of tin loses 1.375 kg in the water and 5 kg of silver loses 0.375 kg, what is the ratio of tin to silver in the bar?

Answer 1

Ratio of tin to silver in the bar is 2:3

Explanation:

We are given the following in the question:

10 kg of tin loses 1.375 kg in the water

Percentage of weight lost by tin =

`(1.375)/(10)* 100\% = 13.75\%`

5 kg of silver loses 0.375 kg

Percentage of weight lost by silver =

`(0.375)/(5)* 100\% = 7.5\%`

20 kg bar loose 2 kg in water.

Percentage of weight lost by metal =

`(2)/(20)* 100\% = 10\%`

Let x be the amount of tin and y be the amount of silver in bar.

Thus, we can find the ratio as:

`(x)/(y) = \frac{\text{Silver's loss - Average loss}}{\text{Average loss - Tin's loss}}\\\\(x)/(y) = (7.5-10)/(10-13.75) = (2)/(3)`

is the required ratio.